Java 中递进式判断的优化方案：如何避免重复的 if-else 语句？

java中递进式判断的优化方案

在java中进行递进式判断时，需要根据每一层的条件是否满足来执行不同的代码逻辑。原始代码中使用大量的if-else语句，代码冗余且可读性差。下面介绍两种优化方案：

方案一：使用switch-case

我们可以先根据不同的情况组合，生成一个对应的状态码。然后通过switch-case语句根据状态码直接执行相应的代码逻辑。该方案可以减少if-else语句的层级，使得代码更加简洁。

private static final int code_condition_one = 0000;
private static final int code_condition_two = 0001;
private static final int code_condition_three = 0011;
private static final int code_condition_four = 0111;
private static final int code_condition_five = 1111;

private static void test(string a,string b,string c,string d){
    switch (init(a,b,c,d)){
        case code_condition_one:
            // do something ...
            break;
        case code_condition_two:
            //do something ...
            break;
        case code_condition_three:
            //do something ...
            break;
        case code_condition_four:
            //do something ...
            break;
        case code_condition_five:
            //do something ...
            break;
    }
}

private static int init(string ... allparam){
    if(allparam == null){
        return 1;
    }
    string resultnumberstr = "";
    for (string s : allparam) {
        resultnumberstr += stringutils.isnotempty(s) ? 0 : 1;
    }
    return integer.valueof(resultnumberstr);
}

方案二：使用反射

该方案通过反射机制，根据不同的状态码动态生成对应的action对象，然后调用对象的特定方法执行代码逻辑。该方案更加灵活，可以根据需要动态添加新的判断条件和执行逻辑。

static class Action{
    private Class targetInvokeClass;
    private String targetMethodName;
    private Class[] parameterTypes;
    private Object[] params;
    private boolean isCurrentClass;
    private boolean isNoParams;

    // getters and setters
}

private static HashMap<Object,Action> ACTION_MAP = new HashMap<>();

private static void test(String a,String b,String c,String d){
    int result = init(a, b, c, d);
    Action action = ACTION_MAP.get(result);
    if(action != null){
        handler(action);
    }else{
        System.out.println("未找到对应映射键");
    }
}

private static void handler(Action action) {
    try {
        Method method = null;
        Class cls = null;
        if (action.isCurrentClass()) {
            method = getMethod(SolutionTwo.class,action.getTargetMethodName(),action.getParameterTypes());
            cls = SolutionTwo.class;
        }else{
            Class targetClass = action.getTargetInvokeClass();
            method = getMethod(targetClass, action.getTargetMethodName(), action.getParameterTypes());
            cls = action.getTargetInvokeClass();
        }
        result = method.invoke(cls.newInstance(), action.getParams());
    } catch (NoSuchMethodException | IllegalAccessException | InvocationTargetException | InstantiationException e) {
        e.printStackTrace();
    }
}

private static Method getMethod(Class cls,String methodName,Class[] parameterTypes) throws NoSuchMethodException {
    return cls.getMethod(methodName,parameterTypes);
}


private static int init(String ... allParam){
    if(allParam == null){
        return 1;
    }
    String resultNumberStr = "";
    for (String s : allParam) {
        resultNumberStr += StringUtils.isNotEmpty(s) ? 0 : 1;
    }
    return Integer.valueOf(resultNumberStr);
}

以上就是Java 中递进式判断的优化方案：如何避免重复的 if-else 语句？的详细内容，更多请关注其它相关文章！